x=(2^-1-2^-2)/2^-3

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Solution for x=(2^-1-2^-2)/2^-3 equation:



x=(2^-1-2^-2)/2^-3
We move all terms to the left:
x-((2^-1-2^-2)/2^-3)=0
We multiply all the terms by the denominator
x*2^-3)-((2^-1-2^-2)=0
We add all the numbers together, and all the variables
x*2^=0
Wy multiply elements
2x^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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